Question

Two Indian tourists in the US cycled towards each other, one from point A and the other from
point B. The first tourist left point A 6 hrs later than the second left point B, and it turned out on
their meeting that he had travelled 12 km less than the second tourist. After their meeting, they kept
cycling with the same speed, and the first tourist arrived at B 8 hours later and the second arrived
at A9 hours later. Find the speed of the faster tourist.

Answer 1

Given:

Point A left by first tourist = 6 hrs late

Time traveled less by first tourist = 12hrs

Late time of first = 8 hrs

Late time of second = 9 hrs

To Find:

Speed of the faster tourist

Solution:

Let the time be = t

Time taken by A to complete the journey =  t + 2 hrs

Time taken by B to complete the journey = t +  9 hrs

Therefore, A is faster

According to the question - (t – 6)/9 = 8/t

Solving for t, we get t = –6 and 12.

Ratio of speeds = 3 : 2  

If the speed of the faster person is 3s, then of the slower person = 2s.

Thus.

12 × 2s – 6 × 3s

= 12 km

s = 2 kmph.

The speed of the faster tourist is 3 × 2 = 6

Answer: Therefore, the speed of faster tourist is 6kmph

Answer 2

Step-by-step explanation:

I have tried to give the detailed explanation.