Two individual forces of magnitude F1, and F2 act
on a body of mass 1 kg as shown in the figure (i)
and (ii). If the net force in case (i) is 3N & the net
force in case (ii) is 9N, then find the magnitude of
forces F1, and F2. (assume F1, > F2,)
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Answered by
14
From figure (i) ,
net force(F') = F1 - F2 .
From figure (ii),
net force (F'') = F1 + F2
Given,
(F1 - F2)(F1 + F2) = 27N
=> F²1 - F²2 = 27
factor's of F = 27 are 1,2,3,7,9 .
If, F1 + F2 = 9N
F1 - F2 = 3N
Hence, F1 = 6N and F2 = 3N .
Hope it's helpful to you.
Please mark as Brainliest answer.
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Answered by
3
Answer:
From figure (i) ,
net force(F') = F1 - F2 .
From figure (ii),
net force (F'') = F1 + F2
Given,
(F1 - F2)(F1 + F2) = 27N
=> F²1 - F²2 = 27
factor's of F = 27 are 1,2,3,7,9 .
If, F1 + F2 = 9N
F1 - F2 = 3N
Hence, F1 = 6N and F2 = 3N .
Hope it's helpful to you.
Please mark as Brainliest answer.
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