Question

Two infinitely long parallel identical wires are at a distance of 1 metre. Both of them carry one ampere of current. The force of attraction per unit length between the two wires is
(A) 2 x 10^-7 N/m
(B) 2 x 10^ -8N/m
(C) 5 x 10^-8N/m
(D) 10^-7 N/m​

Answer 1

Answer:

2×10^-7N/m

Explanation:

• F=μ0I/2πa
• F=μ0I1I2/2πa

μ0=4π×10^-7

I1=1

I2=1

a=1

F=4π×10^-7×1×1/2π×1

F=2×10^-7N/m

Answer 2

The force of attraction per unit length between the two wires is equal to $2\times 10^{-7}\ N/m$.

Explanation:

It is given that,

Distance between two infinitely long parallel identical wires, d = 1 m

Current in both of the wires, $I_1=I_2=1\ A$

To find,

The force of attraction per unit length between the two wires.

Solution.

The force of attraction per unit length between the two wires is given by the following formula as :

$\dfrac{F}{l}=\dfrac{\mu_o I_1I_2}{2\pi d}$

$\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times (1)^2}{2\pi \times 1}$

$\dfrac{F}{l}=2\times 10^{-7}\ N/m$

So, the force of attraction per unit length between the two wires is equal to $2\times 10^{-7}\ N/m$.

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Electric force

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