Physics, asked by suchandradg7856, 11 months ago

Two infinitely long parallel wires are at a distance of 1 meter. Both of them carry 2 Ampere of current. The force of attraction per unit length between the two wires is found to be k 107 N / m . Findk?

Answers

Answered by abhi178
28

Force per unit length between two infinity long parallel wires is given by, \mathbb{F}=\frac{\mu_0i_1i_2}{2\pi d}

where,\mu_0 is permeability of vaccum or air, i_1,i_2 are current through parallel wires respectively and d is the separation between wires.

here, \mu_0 = 4π × 10^-7 Nm/A²

i_1=i_2=2A and d = 1m

so, \mathbb{F} = 4π × 10^-7 × (2)²/(2π × 1)

= 2 × 10^-7 × 4

= 8 × 10^-7 N/m

but given, force per unit length is k × 10^-7 N/m

comparing both sides,

we get, k = 8

Answered by vedantsonawanescitec
14

Answer: I

Explanation:

Force per unit length between two infinity long parallel wires is given by,

where, is permeability of vaccum or air, are current through parallel wires respectively and d is the separation between wires.

here, = 4π × 10^-7 Nm/A²

and d = 1m

so, = 4π × 10^-7 × (2)²/(2π × 1)

= 2 × 10^-7 × 4

= 8 × 10^-7 N/m

but given, force per unit length is k × 10^-7 N/m

comparing both sides,

we get, k = 8

Your rating: Excellent!

5

Read more on Brainly.in - https://brainly.in/question/9390724#readmore

Similar questions