Two inlet pipes a and b can fill an empty cistern in 4 hours and 8 hours, respectively. If both are opened together in the empty cistern,how much time will they take to fill it completely?
Answers
Answer:
if a can fill a cistern in 4 hours and b in 8 hours then if we take them both in one hour then it will be 1 by 4 for a and 1 by 8 for b then if we add A + b gives a 1 by 4 + 1 by 8 gives 3 by 8 then reciprocal it will give 8 by 3 gives 2 hours and 30 minutes
Answer:
Step-by-step explanation:Work done by pipe A in one hour=1/4
Work done by pipe Bi one hour=1/8
[ A + B ] ∴1/4+1/8 [LCM=8]
= 3/8 hours
Total time needed to complete = 1÷3/8 hours
=1x8/3 hours
8/3 hours = 2.4 hours
= 2 Hours 40 Minutes