Two insulating small sphere are rubbed against each other and place 2cm apart if they attract each other with a firce of 0.4N how many electron were transfered from one sphere to the other during rubbing
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Answer:
n = 2 × 10¹³ electron
Explanation:
F = kq^2/r^2
0.1 = 9 x 10^9 q^2/0.96x0.96
q^2 = 0.1 x 0.96 x 0.96/ 9 x 10^9
q^2 = 1.024 x 10^-11
q = 3.2 x 10^-6
q = ne ; n = q/e
n = 3.2 x 10^-6/ 1.6 x 10^-19
n = 2 x 10^13
Electron transferred = 2 x 10^13
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