Question

Two integers differ by 12 and the sum of their squares is 74. find the integers

Answer 1

according to problem :


 


A-B=12 and A^2 + B^2 =72 

A-B=12 
A=12+B 

A^2 + B^2 =74 
(12+B)^2 + B^2 =74 
12^2 + 2*12*B + B^B + B^2 = 74 
144+24B+2B^2=74 
144-74+24B+2B^2=0 
70+24B+2B^2=0 
35+12B+B^2=0 
(7+B)(5+B)=0 
B=-7 or B=-5 

A-B=12 
A-(-7)=12 
A+7=12 
A=12-7 
A=5