Question

two integers whose sum is 3 and product is -108

Answer 1

Answer:

Let 2 integers be a, b

A/Q,

a+b=3

ab=-108 => b=-108/a

So,

a+b=3

=> b = 3-(-108) = 3+108 =111 ans.

ab=-108

a= (-108)/111

a= 0.973 approx ans.

Answer 2

Let n,m be those no.

Then,

• n+m = 3
• nm = - 108

m= -108/n

n+m = 3

n = 3 + 108/n = (3n+108)/n

or,

nm=-108

=》nm = (-108/3)×3 = -36×3 = -36/(n+m)

but this was just an experiment, yo will not do these..XD

ANSWER:

• equn1 ÷ equn2
• nm ÷ (n+m) = -36

• or make in a²+b+c =0 form