Two interior angles of a parallelogram are (3x + 61)° and (2x + 19)°. Find each angle of theparallelogram.
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Since adjacent angles of a parallelogram are supplementary . Therefore,
3x+61+2x+19=180
5x+80=180
5x=180-80
5x=100
x= 100/5
x= 20
one angle= 3x+61=3×20+61=121
other angle =2x+19= 2×20+19=59
The measure of each angle of the parallelogram.[Opp.angles of parallelogram are equal]
=121°,59° ,121°,59°
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