Two interior angles on same side of transversal measure (a-6)and (5a-6) .find the measure of each angle
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if two lines are parallel
sum of interior angles on same side of transversal are supplementary
(a-6)+(5a-6)=180
6a-12=180
6a=180+12
6a=192
a=192/6
a=32
therefore
first angle = a-6=32-6=26
second angle = 5a-6= 5*32-6
=160-6
=154
sum of interior angles on same side of transversal are supplementary
(a-6)+(5a-6)=180
6a-12=180
6a=180+12
6a=192
a=192/6
a=32
therefore
first angle = a-6=32-6=26
second angle = 5a-6= 5*32-6
=160-6
=154
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