Question

Two investments totaling $50,000 produce an annual income of $4795. One investment yields 10% per year, while the other yields 9% per year. How much is invested at each rate?

Answer 1

$\huge \bf\mathfrak \red{ANSWER:}$

RS.20,500 AND RS. 29,500

$\boxed{Step-by-step verification:}$

Let, one investment be x and another be 50,000-x.

Then,

Income from first investment

= 9% of x

= 0.09x

Again,

Income from second investment

=10%of(50000−x)

=5000−0.1x

So,

Total income=I¹+I²

Or,

4795=0.09x+5000−0.1x

Or,

205 = 0.01x

•°•

x = 20500x=20500

Again,

another investment

=50000−20500

=29500

So, the two investments are Rs. 20,500 and Rs. 29,500.

Answer 2

Answer:

Step-by-step explanation:

let I st investment=x then  2nd =50000-x

10% x=x/10

9% of(50000-x)=9/100(50000-x)

9/100(50000-x)+x/10=4795

9*500-9x/100+x/10=4795

multiplying by 100

450000-9x+10x=479500

x=479500-450000

x=29500

II investment=50000-29500=20500