Question

Two ions A and B have radii of 0.88 Aº and
2 Aº respectively. What will be the type of
crystal?

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Answer 1

Answer:

Hope this attachment helps you dear......

Answer 2

Answer:

Explanation:

Two ions A and B have radii of 0.88 Aº and 2 Aº respectively. What will be the type of crystal?

Given:

Two ions A and B have radii of 0.88 Aº and 2 Aº

A =  0.88 Aº

B =  2 Aº

Let us look at the radius ratio of the compound AB.

we know that,

Radius ratio of the compound AB.

Here,

$\frac{r(A^{+}) }{r(B^{-}) }=\frac{0.882}{2} =0.44$

Radius ratio falls in the range $0.414$$- 0.732$

Approximately,

We can see that radius ratio 0.44 lies in the range of $0.414$$- 0.732$

Crystal is of fcc type.

Hence, it is proved two ions A and B have radii of 0.88 Aº and 2 Aº

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