Question

Two iron spheres are suspended from strings and separated by a distance of 9.0 meters. The
charge on one sphere is 7.0*10^−8 C and the other −3.0 *10^−5 C. What is the electric force on the spheres?
Group of answer choices

A repulsive force of 2.3*10^-4 N

An attractive force of 2.3*10^-4 N

A repulsive force of 4.6*10^-4 N

An attractive force of 4.6*10^-4 N

Answer 1

Force between 2 charged bodies

=(charge on first body×charge on second body)/distance^2

=q1q2/r^2

use this to find answer.

Answer 2

The force between charges is $2.3\times 10^{-4}\ N$ and the force is attractive.

Explanation:

The charge on one sphere, $q_1=7\times 10^{-8}\ C$

The charge on another sphere, $q_2=-3\times 10^{-5}\ C$

The separation between spheres, d = 9 m

It is required to find the electric force on the spheres. It is based on the electrostatic force of attraction. These two charges have opposite charge, they will attract each other. The force is given by :

$F=k\dfrac{q_1q_2}{r^2}\\\\F=9\times 10^9\times \dfrac{7\times 10^{-8}\times 3\times 10^{-5}}{(9)^2}\\\\F=2.3\times 10^{-4}\ N$

So, the force between charges is $2.3\times 10^{-4}\ N$ and the force is attractive.

Learn more,

Electric force

https://brainly.in/question/14115211