Two isolated point poles of strength 30 am and 60 am are placed at a distance of 0.3m the force of repulsion between them is
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Given ⇒
Mass of the First pole(m₁) = 30 A-m.
Mass of the Second Pole(m₂) = 60 A-m.
Distance between them (r) = 0.3 m.
We know, μ₀/4π = 10⁻⁷ N/A²
Now, Using the Formula,
Force of Repulsion (F) = μ₀/4π × m₁m₂/r²
⇒ F = 10⁻⁷ × 30 × 60/(0.3)²
⇒ F = 10⁻⁷ × 1800/0.09
⇒ F = 20000 × 10⁻⁷
∴ F = 2 × 10⁻³ N.
Hence, the Force of Repulsion between the Isolated point poles is 2 × 10⁻³ N.
Hope it helps.
Mass of the First pole(m₁) = 30 A-m.
Mass of the Second Pole(m₂) = 60 A-m.
Distance between them (r) = 0.3 m.
We know, μ₀/4π = 10⁻⁷ N/A²
Now, Using the Formula,
Force of Repulsion (F) = μ₀/4π × m₁m₂/r²
⇒ F = 10⁻⁷ × 30 × 60/(0.3)²
⇒ F = 10⁻⁷ × 1800/0.09
⇒ F = 20000 × 10⁻⁷
∴ F = 2 × 10⁻³ N.
Hence, the Force of Repulsion between the Isolated point poles is 2 × 10⁻³ N.
Hope it helps.
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