Question

Two isosceles triangle s have equal vertical angles and thier areas are in tne ratio 36:25 find the ratio of their corresponding heights

Answer 1

Answer:

Step-by-step explanation

We can say that both the triangles are similar....

In the similarity case:-

⇒Area of △ABC /Area of △DEF

=(AB)2 / (DE)2                          corresponding sides square

=(AM)2 /( DN)2            height

⇒36 / 25=(AM)2(DN)2  

=√36 / 25= Ratio of their height

⇒ Ratio of height = 6 /5

Regards..............