Two isosceles triangle s have equal vertical angles and thier areas are in tne ratio 36:25 find the ratio of their corresponding heights
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Step-by-step explanation
We can say that both the triangles are similar....
In the similarity case:-
⇒Area of △ABC /Area of △DEF
=(AB)2 / (DE)2 corresponding sides square
=(AM)2 /( DN)2 height
⇒36 / 25=(AM)2(DN)2
=√36 / 25= Ratio of their height
⇒ Ratio of height = 6 /5
Regards..............
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