Question

two isosceles Triangles have equal bases and their areas are in ratio 16 ratio 49 find the ratio of their corresponding altitude

Answer 1

Area of isosceles triangle = $\frac{1}{2} \times {base} \times {Height}$

$A_{1}=\frac{1}{2} \times a \times h_{1}\\\\ A_{2}=\frac{1}{2} \times a \times h_{2}\\\\ \frac{A_{1}}{A_{2}}=\frac{h_{1}}{h_{2}}$,

Where a = base of  both isosceles triangle

$\frac{A_{1}}{A_{2}}=\frac{16}{49}\\\\ \frac{h_{1}}{h_{2}}=\frac{A_{1}}{A_{2}}\\\\ \frac{h_{1}}{h_{2}}=\frac{16}{49}$

Answer 2

Answer:

h1=16,h2

as the base of two isosceles triangles are equal the ratio of their heights =ratio of their areas