Question

two items were bought at the same cost. one was sold at a profit of 10% and the other at the profit of 15%. if the difference in their profit is $7.5, find the cost price of each item

Answer 1

see
CP is same, let it be x
SP for the first article after getting 10% profit=x×1.1
for second=x×1.15
x×1.15-x×1.10=7.5________(given)
x×0.05=7.5
x=7.5/0.05
=750/5=150

So CP=$150

Answer 2

Cost Price of Items is $150

Step-by-step explanation:

Let us consider the two items as A & B  

And the Cost Price of Purchasing them be $ x

Selling Price of A with 10% Profit = x + 10% of x

Selling Price of B with 15% of Profit = x + 15% of x

Given, the difference of Profit earned on selling = $ 7.5

According to question,

• Selling Price of A - Selling Price of B = The Difference of Profit Earned on Selling the Items

(x + 15% x) - (x + 10% x) =7.5

⇒ $x + \frac {15}{100} x - (x + \frac {10}{100}x) = 7.5$

⇒ $x - x + \frac {3}{20}x - \frac {1}{10}x = 7.5$

⇒ $\frac {1}{20}x = 7.5$

⇒ x = $7.5 \times 20$

= $ 150 the Cost Price of Items