Question

two items were bought at the same cost one was sold at a profit of 10% and the other at a profit of 15%. If the difference in their profit is rupees 7.5 find the cost price of each item.


if you answered correctly I will mark answer as brainlist ❣️​

Answer 1

Step-by-step explanation:

For 1st item,

Cost price = y , Selling price = x;

10%profit on y will be (110*y)/100 ;

so, x=(110*y)/100;

x=(11*y)/10 .........(1);

For 2nd item,

cost price = z , Selling price =x ;

10% loss on z will be (90*z)/100 ;

so, x=(90*z)/100;

x=(9*z)/10 ........(2);

from (1) & (2),

11*y=9*z;

so y/z=9/11;

so lets put y as 9 and z as 11;

x=(90*11)/100 ;

x=99;

now if the selling price of both is 99 each;

cost price of 1st item will be 90 and cost price of 2nd item will be 110;

total cost price = 90+110 =200;

total selling price = 99+99 =198;

Percentage loss = ((200-198)*100)/200;

Percentage loss = 1%

:)