Question

Two jackets were bought at the same cost. One was sold at a profit of 9% and another at the profit of 15% .If the difference in the selling price of both jackets was Rs105 ,then what was the cost price of each jacket ?

Answer 1

Answer:

let x be the cp

then 15x/100+x-x-9x/100 = ₹1750

Answer 2

The cost price of the jacket was Rs. 1750.

• Two jackets were brought at the same cost.

• Let the cost price of the jacket be x.

• One jacket is sold at 9% profit.

Selling price of the jacket is x + 0.09x = 1.09x

• Other jacket is sold at 15% profit.

Selling price of the other jacket is x + 0.15x = 1.15x

• Now the difference in the selling price of the jacket is Rs. 105.

• Therefore,

1.15x - 1.09x = 105

0.06x = 105

x = 105/0.06

x = 1750

• Cost price of the jacket was Rs. 1750.