Question

Two jars a and b contain a mixture of two liquid X and y in ratio of 2:3 and 4:5 respectively.if mixture from jar a and b are mixed in ratio 1:2 then find the ratio of X and y in final mixture.​

Answer 1

Answer:

In new mature" X/Y=68 / 77"

Explanation:

Since:

Jar A contain X and Y in ratio = 2 / 3

The 5 units of mixture in jar A contain X and Y = 2X + 3Y

The 1 unit of mixture in jar A contain X and Y = (2/5)*X + (3/5)*Y     ....(1)

similarly

Jar B contain X and Y in ratio = 4 / 5

The 9 units of mixture in jar B contain X and Y = 4X + 5Y

The 1 unit of mixture in jar B contain X and Y = (4/9)*X + (5/9)*Y   .....(2)

The new jar C contain A and B in ratio = 1 / 2

The 3 units of mixture in jar C contain A and B = 1A + 2B

The 1 unit of mixture in jar C contain A and B = (1/3)*A + (2/3)*B   ......(3)

By putting the values of one unit of A and B from equation (1) and (2) respectively in equation (3) we get

1 unit of mixture in jar C has X and Y= (1/3)((2/5)X+(3/5))Y+(2/3)((4/9)X+(5/9)Y)

1 unit of mixture in jar C contain X and Y =(68/135)X + (77/135)Y

SO the jar C contain X and Y in ratio=(68/135)÷(77/135)=68/77

Hence in Jar C ; X/Y=68 / 77.

Answer 2

Answer:

Answer: The ratio of X and Y in final mixture is 5:3. explanation:Since it is given that : Ratio of mixture in Jar A is 2:3.Ratio of mixture in Jar B is 4:5/ Now, If mixture from Jar A and B are mixed in ratio 1:2. So, we will apply mixture and allegation: Jar A             Jar B.15     :      9.  5     :      3.So, the ratio of X and Y in final mixture is 5:3.

Explanation: