Math, asked by muradhossain0411, 8 months ago

Two jars contain equal quantities of 40% alcohol. Anju changed the concentration of the first jar to 50% by adding extra quantity of pure alcohol. Sonali changed the concentration of the second jar to 50% by replacing a certain quantity of the solution with pure alcohol. By what percentage is the quantity of alcohol added by Anju more than that replaced by Sonali ?

Answers

Answered by monikamota705
0

Answer:

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Step-by-step explanation:

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Answered by apekshacuteipie
0

Answer:

0% alcohol solution is mixed with 19% alcohol solution to give 26% alcohol solution.

w1/w2 = (A2 - Aavg)/(Aavg - A1) = (40 - 26)/(26 - 19) = 14/7 = 2/1

So 2 parts of 19% solution were mixed with 1 part of 40% solution. This means that 2/3rd of the 40% solution was replaced by 19% solution.

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