Question

Two jets leave Dallas at the same time and fly in opposite directions. One is flying 50 mph faster than the other. After 2 hours they are 2500 miles apart. Write and solve an equation to find the speed of each jet.

Answer 1

Let's assume

speed of second jet is x mph

we are given

One is heading west 50 mph faster than the other flying east

so, speed of second jet is x+50

they are moving in opposite direction

now, we will find distance travelled by them after 2 hours

Distance travelled by second jet after 2 hours:

we know that

distance =speed*time

so, di = X * 2

so, di = 2x

Distance travelled by first jet after 2 hours:

we know that

distance =speed*time

sod2 = (x + 50) * 2

so, di 2x + 100

now, we can find total distance

so, d=d1 + d2

d = 2x + 2x + 100

we are given that distance as 2500

so, we can set it to 2500

2500 2x + 2x + 100

now, we can solve for x

4x 2400

X = 600

Then the speed of the faster one is x + 50. the speed of the fast jet is x + 50 = 650 miles per hour.

Answer:- 650 Miles per hour

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