Math, asked by sarathrajendran3596, 10 months ago

Two kinds of vodka are mixed in the ratio 1:2 and 2:1 and they are sold fetching the profit 10% and 20% respectively. If the vodkas are mixed in equal ratio and the individual profit percent on them are increased by 4/3 and 5/3 times respectively, then the mixture will fetch the profit of

Answers

Answered by swagMAMA
0

Answer:

the profit of = 20%.

Step-by-step explanation:

=> The profit on the first kind of vodka = x%;

=> The profit on the second kind of vodka = y%.

=>When they are mixed in the ratio 1:2 (total of 3 parts) the average profit is 10%: (x + 2y)/3 = 10.

=> When they are mixed in the ratio 2:1 (total of 3 parts) the average profit is 20%: (2x + y)/3 = 20.

Solving gives: x = 30% and y = 0%.

After the individual profit percent on them are increased by 4/3 and 5/3 times respectively the profit becomes 40% and 0%, on the first and te second kinds of vodka, respectively.

=> If they are mixed in equal ratio (1:1), then the mixture will fetch the profit of (40 + 0)/2 = 20%.

therefore the answer is 20%

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