Question

Two lamps, one rated 100 W; 220 V, and the other 60 W; 220 V, are connected

in parallel to electric mains supply. Find the current drawn by two bulbs from

the line, if the supply voltage is 220 V.

Answer 1

Answer:

Step-by-step explanation:

P=VI

so Powers of the lamps are 100 W and 60 W respectively along with 220 V potential difference

So

I=P/V

For lamp 1

I=100/220=5/11 A

For lamp 2

I=60/220=3/11 A

Now calculating resistances for both of them

R1=V/I

=220*11/5

=2420/5 Ohms

R2=220*11/3

=2420/3 Ohms

Now 1/Rp=1/R1+1/R2

1/Rp=3+5/2420

=8/2420

Therefore Rp=2420/8

=302.5 Ohms

Now taking R= 302.5

V=220V

We apply

I=V/R

I=220/302.5

=0.72 Amperes (approx)

Answer 2

Hello friend___❤

Here is your answer ✒

For the 1st lamp:

Power P1 = 100 W and

Potential difference V = 220 V

Therefore,

I1= P1/ V = 100/220 = 0.455 A

For the 2nd lamp:

Power P2 = 60 W and

Potential difference V = 220 V

Therefore,

I2= P2/ V =60/ 220 = 0.273 A

So, the net current drawn from the supply is given by

= I1 + I2 = 0.455 + 0.273 = 0.728

I hope, this will help you___❤❤

Thank you

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