Question

two lamps one rated 100 w at 220 V and other 60 w at 220 V are connected in parallel to electric main supply what is the current drawn from the line if the supply voltage is 220 V

Answer 1

Depends. In this millennium, a normal outlet is 240Vrms. Your grandfather's house may have been 220Vrms

Assuming you bring the two light bulbs into your time machine, or you have a special interest power supply.

Then your effect is equal to current times voltage. In parallel, the two bulbs have the same voltage, but separate current.

I1 = 100/220 = 5/11A

I2 = 60/220 = 3/11A

So the combined current drawn from your supply is 8/11 = 0.7A rms

So, what's the RMS? Roughly, it means “what matters to the user”. Because the supply is alternating current, the sine wave is super complicated, and the peaks voltage are about 620v apart, gently fluctuating in a some wave. Your light bulb can reasonably be averaged out as a resistor, gently washing between light and dark. The total output energy over time is best described with the RMS, so that's what everybody uses.

Your grandfather's power company sucked! They gave him 220v plus or minus 10 percent, sometimes 198v and sometimes 242v, dimming and frying his equipment. About 40 years ago, they changed the contract, so they'd mostly provide 240v, officially plus 5 percent, minus 15 percent, but in reality very consistent.

It baffles my mind that we still talk about 110v and 220v, when it hasn't been like that since my childhood, sometime last millennium :-)

Answer 2

Hello friend___❤

Here is your answer ✒

For the 1st lamp:

Power P1 = 100 W and

Potential difference V = 220 V

Therefore,

I1= P1/ V = 100/220 = 0.455 A

For the 2nd lamp:

Power P2 = 60 W and

Potential difference V = 220 V

Therefore,

I2= P2/ V =60/ 220 = 0.273 A

So, the net current drawn from the supply is given by

= I1 + I2 = 0.455 + 0.273 = 0.728

I hope, this will help you___❤❤

Thank you

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