. Two lamps, one rated 100 W at 220 V and the other 200 W at 220V are connected (i) in series and (ii) in parallel to
electric main supply of 220V. Find the current drawn in each case.
Answers
Answered by
2
R1= V^2/P1=220×220/100=484ohm
R2=V^2/P2=220×220/200=242ohm
In series
Rs=R1+R2=484+242=726ohm
Therefore,Is=V/Rs=220/726=10/33A=0.30A
In parallel
1/Rp=1/R1+1/R2=1/484+1/241
Rp=484/3ohm
Ip=V/Rp=220×3/484=30/22A=1.36A
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Answered by
0
1st lamp
power=100w
V=220v
for 1st lamp current drown is
P=VI
then, I=P/V
I=100/220
=>0.45A(approx)
For 2nd lamp
power=200w
V=220v
applying
P=IV
=>I=P/V
=>I=200/220
=>I=0.99A
1st = 0.45A
2nd=0.99A
Bro your answer is wrong
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