Two lamps one rated 100 w at 220 v at the and the other 200 w at 2:20 we are connected 1 in series and 2 in parallel to the electric main supply of 220 we find the current drawn in each case
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this is in my book but not done till let
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Answer:
I_series = 0.30 A
I_parallel = 1.36 A
Explanation:
Given :
Two lamps power as 100 W and 200 W at 220 V.
We have resistance formula :
R₁ = 220 × 220 / 100 = 484 Ω
R₂ = 220 × 220 / 200 = 242 Ω
In series combination :
R_net = 484 + 242 Ω
= > 726 Ω
We have ohm's law :
V = I R
I = 220 / 726 A
I = 0.30 A
( ii ) In parallel combination :
1 / R_net = 1 / 484 + 1 / 242 Ω
R_net = 484 / 3 Ω
Given : V = 220 V
I' = 220 / 484 × 3 A
I' = 1.36 A
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