Two lamps one rated 100W - 20V and other 60W - 220 V are connected in parallel to a 220 volt supply. What is the current drawn from the supply line?
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Answered by
0
as they are in parallel , so
I = I¹ + I²
I¹= 100/20. (P=VI)
I¹=5
I²=60/220
=3/11
I=5+3/11
=58/11
I = I¹ + I²
I¹= 100/20. (P=VI)
I¹=5
I²=60/220
=3/11
I=5+3/11
=58/11
manny3:
bta
Answered by
3
Power = P = 100 W
Voltage = V = 220v
Resistance = R
P = V²/R
100 = 220 ×220/R
R = 220 × 220/100
= 484 Ω
==========================
Power = P = 60 W
Voltage = V = 220v
Resistance = R
P = V²/R
60 = 220 × 220/R
R = 220× 220/60
= 806.7 Ω
=========================
As the resistors are connected in parallel ,
total resistance = 1/R
1/R = 1/484 + 1/806.7
= 806.7 + 484/484×806.7
= 1290.7/390442.8
R = 390442.8/ 1290.7 = 302.5 ohms
Total resistance = 302.5 Ω
I = current
V = IR
220 = I × 302.5
I = 220/302.5
= 0.73 A
The current drawn is 0.73 A
Hope it helps !!!!
Plz mark as brainliest
Voltage = V = 220v
Resistance = R
P = V²/R
100 = 220 ×220/R
R = 220 × 220/100
= 484 Ω
==========================
Power = P = 60 W
Voltage = V = 220v
Resistance = R
P = V²/R
60 = 220 × 220/R
R = 220× 220/60
= 806.7 Ω
=========================
As the resistors are connected in parallel ,
total resistance = 1/R
1/R = 1/484 + 1/806.7
= 806.7 + 484/484×806.7
= 1290.7/390442.8
R = 390442.8/ 1290.7 = 302.5 ohms
Total resistance = 302.5 Ω
I = current
V = IR
220 = I × 302.5
I = 220/302.5
= 0.73 A
The current drawn is 0.73 A
Hope it helps !!!!
Plz mark as brainliest
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