Two lamps one rated 100w at 220 v,and the other 60w at 220 v,are connected in parallel to electric mains supply . what current is drawn from the line if the supply voltage is 220?
Answers
Answer:
lamp 1 = 100w
lamp 2 = 60w
Explanation:
lamp 1 = (220/220)²×100w
lamp 2 =(220/220)²×60w
Answer:
Both the bulbs are connected in parallel. Therefore, potential difference across each of them will be 220 V, because no division of voltage occurs in a parallel circuit.
Both the bulbs are connected in parallel. Therefore, potential difference across each of them will be 220 V, because no division of voltage occurs in a parallel circuit.Current drawn by the bulb of rating 100 W is given by,Power = Voltage x Current
Both the bulbs are connected in parallel. Therefore, potential difference across each of them will be 220 V, because no division of voltage occurs in a parallel circuit.Current drawn by the bulb of rating 100 W is given by,Power = Voltage x CurrentCurrent = Power/Voltage = 60/220 A
Both the bulbs are connected in parallel. Therefore, potential difference across each of them will be 220 V, because no division of voltage occurs in a parallel circuit.Current drawn by the bulb of rating 100 W is given by,Power = Voltage x CurrentCurrent = Power/Voltage = 60/220 AHence, current drawn from the line = 100/220 + 60/220 = 0.727 A