Question

Two lamps, one rated 110w at 220v and the other 60w at 220v are connected in parallel to electric mains supply. What current is drawn from the line if the supply voltage is 220v


0.737 A


0.717 A


0.607 A


0.773 A

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Answer 1

Answer:

HI !

Power = P = 100 W

Voltage = V = 220v

Resistance = R

P = V²/R

100 = 220 ×220/R

R  = 220 × 220/100

     = 484 Ω

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Power = P = 60 W

Voltage = V = 220v

Resistance = R

P = V²/R

60 = 220 × 220/R

R = 220× 220/60

    = 806.7 Ω

=========================

As the resistors are connected in parallel , 

total resistance = 1/R

1/R = 1/484 + 1/806.7

      =  806.7 + 484/484×806.7

      = 1290.7/390442.8

R = 390442.8/ 1290.7 = 302.5 ohms

    

  Total resistance = 302.5 Ω

I = current

V = IR

220 = I × 302.5

I = 220/302.5

   = 0.73 A

The current drawn is 0.73 A

Answer 2

Answer:

here is your answer for your question

Explanation:

Both the bulbs are connected in parallel. Therefore, potential difference across each of them will be 220 V, because no division of voltage occurs in a parallel circuit.

Current drawn by the bulb of rating 100 W is given by,Power = Voltage x Current

Current = Power/Voltage = 60/220 A

Hence, current drawn from the line = 100/220 + 60/220 = 0.727 A

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