Two lamps one rated l100 watt at 220 volts and the other 60 watt bulb are connected in parallel to a 220 volt supply.What current is drawn from the supply line?
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plz check on the internet
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Hello friend___❤
Here is your answer ✒
For the 1st lamp:
Power P1 = 100 W and
Potential difference V = 220 V
Therefore,
I1= P1/ V = 100/220 = 0.455 A
For the 2nd lamp:
Power P2 = 60 W and
Potential difference V = 220 V
Therefore,
I2= P2/ V =60/ 220 = 0.273 A
So, the net current drawn from the supply is given by
= I1 + I2 = 0.455 + 0.273 = 0.728
I hope, this will help you___❤❤
Thank you
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