Question

Two large, thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude 17.0 × 10−22 C/m2. What is E:
(a) in the outer region of the first plate,
(b) in the outer region of the second plate, and

(c) between the plates?

Answer 1

Explanation:

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The situation is represented in the following figure.

A and B are two parallel plates close to each other. Outer region of plate A is labelled as I, outer region of plate B is labelled as III, and the region between the plates, A and B, is labelled as II.

Charge density of plate A, σ=17.0×10

−22

C/m

2

Charge density of plate B, σ=−17.0×10

−22

C/m

2

Electric field in regions can be found with the help of Gauss Law. In the regions, I and III, electric field E is zero. This is because charge is not enclosed by the Gaussian surfaces of the plates.

Electric field E in region II is given by the relation,

E=

∈

0

σ

Where,

∈

0

= Permittivity of free space =8.854×10

−12

N

−1

C

2

m

−2

∴E=

8.854×10

−12

17.0×10

−22

=1.92×10

−10

N/C

Therefore, electric field between the plates is 1.92×10

−10

N/C.