Question

Two largest metel sheets having surface charge density

Answer 1

Explanation:

Electric field due to sheet A, is

E

1

=

2ε

0

σ

i {in right side of the sheet}

Also, electric field due to sheet B, is

E

2

here is your answer mate

=

2ε

0

σ

i {in left side of the sheet}

∴ Resultant electric field by parallelogram law of vector addition,

E

=

E

1

+

E

2

{∵θ=0

0

between

E

1

&

E

2

}

=

2ε

0

σ

+

2ε

0

σ

E

=

ε

0

σ