Two legs of a right angled triangle are in the ratio 3:4.find the shortest leg,if the hypotenuse is 75cm.
Answers
Answered by
12
the shortest leg is 45cm
let legs are 3x&5x
then,
75=√3x^2+4x^2
75=5x
x=15
3x=45
let legs are 3x&5x
then,
75=√3x^2+4x^2
75=5x
x=15
3x=45
somen2:
thanks
Answered by
33
Ratio of two legs = 3:4
let 1st leg be = 3x
let 2nd leg be = 4x
We know,
Pythagoras Theorem!
H² = B² + P²
(75)² = (3x)² + (4x)²
5625 = 9x² + 16x²
5625 = 25x²
5625/25 = x²
√225 = x
15 = x
Now,
1st leg = 3x = 3 * 15 = 45 cm
2nd leg = 4x = 4*15 = 60 cm
hence, the shortest leg = 45 cm
let 1st leg be = 3x
let 2nd leg be = 4x
We know,
Pythagoras Theorem!
H² = B² + P²
(75)² = (3x)² + (4x)²
5625 = 9x² + 16x²
5625 = 25x²
5625/25 = x²
√225 = x
15 = x
Now,
1st leg = 3x = 3 * 15 = 45 cm
2nd leg = 4x = 4*15 = 60 cm
hence, the shortest leg = 45 cm
Similar questions