two legs of a right triangle are in the ratio 3:4. find the shortest leg if the hypotenuse is 75 cm
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(H)²=(B)²+(P)I
(H)²=(3X)²+(4X)²
(75)²=9X²+16X²
5625=25X²
X²=5625÷25
X²=225
X²=(15)²
X=15
Therefore, the shortest leg is 15cm
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(H)²=(3X)²+(4X)²
(75)²=9X²+16X²
5625=25X²
X²=5625÷25
X²=225
X²=(15)²
X=15
Therefore, the shortest leg is 15cm
Hope it helps
Please mark me as Brainliest
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