two lens are in the ratio 4:1 what would be the focal length .
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Answer:
For an achromatic combination,
w
1
f
1
+
w
2
f
2
=0
Also, the effective focal length of the combination will be:
f
1
=
f
1
1
+
f
2
1
Solving these simultaneously and substituting the values, the obtained focal lengths are, f
o
=15 and f
e
=−20
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