two lens have focal length 100 and -50cm. find the power of combination og the lens?
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Hey!!
This is your answer.
Focal length of First Lens = 100 cm = 1 m
Power of First Lens = 1/f (in m) = 1 D
Focal length of second lens = -50 cm = -0.5 m
power = 1/-0.5 = -2 D
P (eq) = P1 + P2 + •••••• + Pn
= 1 - 2
= -1 D
hence the power of combination is -1 D
Hope It Helps
This is your answer.
Focal length of First Lens = 100 cm = 1 m
Power of First Lens = 1/f (in m) = 1 D
Focal length of second lens = -50 cm = -0.5 m
power = 1/-0.5 = -2 D
P (eq) = P1 + P2 + •••••• + Pn
= 1 - 2
= -1 D
hence the power of combination is -1 D
Hope It Helps
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