two lenses of power 6d and -1.5d.find the focal length and mention the nature of each lens
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in the first situation the nature is real and virtual.
in the second situation the nature is virtual and erect.
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CASE 1:
Here P=+D Since power is positive , so the lens is convex lens
Focal length, f = 1/P=1/2=0.5m=50cm
CASE 2:
Now,P=-4 Since power is negative ,so lens is concave.
Focal length,f=1/P=1/-4=-0.25m=-25cm
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