Question

two liens are given parallel the equation of one of the line is 4x+3y=14 then find theequation of the second line​

Answer 1

Answer:

Equation of a line ax + by + c = 0 parallel to given line is ax + by + k = 0 here k is any real number. Therefore , Required parallel line is 4x + 3y = k Example : 4x + 3y = 5 , 4x + 3y = - 7Read more on Sarthaks.com - https://www.sarthaks.com/838092/lines-given-parallel-the-equation-one-the-equation-then-find-the-equation-the-second-line

Answer 2

Answer:

Your answer is

Step-by-step explanation:

4x+3y-14=0 (first line)

here,

a1=4, b1=3, c1=14

we have the condition of parallel lines that

a1 = b1 ≠ c1

a2 b2 c2

So,

4 = 3 ≠ -14

8 6 7

Hence, the second line is

8x+6y+7

HOPE IT IS HELPFUL......