two light wave from coherent sources superpose at a point A with phase difference 0 & at point B with phase difference of Π/2 calculate ratio of resultant intensities of point A&B
1) 1:1
2) 2:1
3) 4:1
4) 1:4
answer this question and explain please
Answers
Answer:I=kA
2
cos
2
(
2
∣theta
)
When both the waves reach in the same phase, then
θ=0
o
I
1
=kA
2
cos
2
(
2
0
o
)
I
1
=kA
2
[cos0
o
=1] ------- (1)
When both the waves reach with phase difference 90
o
.
θ=90
o
I
2
=kA
2
cos
2
(
2
90
o
)
I
2
=kA
2
cos
2
(45
o
)
I
2
=kA
2
(
2
1
) ----- (2)
I
2
I
1
=
kA
2
(1/2)
kA
2
=
1
2
Explanation:
Answer:
PHYSICS
avatar
Asked on December 20, 2019 by
Santanu Sethupathy
Waves from two sources superpose on each other at a particular point amplitude and frequency of both the waves are equal. The ratio of intensities when both waves reach in the same phase and they reach with the phase difference of 90
∘
will be
Help best friend
Study later
ANSWER
Relation between intensity f
Amplitude
I=kA
2
cos
2
(
2
∣theta
)
When both the waves reach in the same phase, then
θ=0
o
I
1
=kA
2
cos
2
(
2
0
o
)
I
1
=kA
2
[cos0
o
=1] ------- (1)
When both the waves reach with phase difference 90
o
.
θ=90
o
I
2
=kA
2
cos
2
(
2
90
o
)
I
2
=kA
2
cos
2
(45
o
)
I
2
=kA
2
(
2
1
) ----- (2)
I
2
I
1
=
kA
2
(1/2)
kA
2
=
1
2