Two like charges each of 20 µC are placed 20 cm apart in a medium of dielectric constant 2.5. Find the force between them. (go = 8.85 * 10 ^ - 12 * C ^ 2 / N * m ^ 2)
Answers
Answer:
Two like charges each of 20 µC are placed 20 cm apart in a medium of dielectric constant 2.5. Find the force between them. (go = 8.85 * 10 ^ - 12 * C ^ 2 / N * m ^ 2)
Explanation:
answer in the picture
Given
two like charges when placed in a medium of dielectric constant of 2.5 at a distance of 0.1 m repel each other with a force of 1 N.
To Find
The force between them when they are placed 0.05 m apart in air.
Working formula
Force between charge particles placed in air
Where, K = and r is the distance between the charged particles.
Force between charge particles placed in a dielectric medium
Here, if the distance between the particles is r, we use the same formula as that of air ,but the new distance is given as is the dielectric constant of the medium.
Calculations
0.1 m distance in a dielectric medium of constant 2.5 gives a distance m distance in air.
Hence,when placed 0.5 m apart , force = 1 N. Thus, we have to find force when they are placed 0.05 m apart.
Hence, the force when they are placed in air is 100 N