Question

Two like charges of magnitude 10^-9 coulomb each are separated by a distance of 2 m in free space. If the
distance between the charges is increased to 4m then the ratio of electric potential energies is [ ]​

Answer 1

Two like charges of magnitude 10^-9 coulomb each, are separated by a distance of 2 m in free space. If the distance between the charges is increased to 4m then, the ratio of electric potential energies is 2

• Given that :

Both charges have same charge of equal magnitude so, let q1 = q2 = q, d = 2m and d' = 4m.

• We know that, the electric potential energy of two charge particles q and Q at a distance d is given by-

E = kQq/d

• Applying the above equation, we get-

E1 = kq^2/d

and

E2 = kq^2/d'

• The ratio of the two electric potential energies is

E1/E2 = (kq^2/d) / (kq^2/d')

• E1/E2 = d'/d = 4/2 = 2

This is our required ratio.

Answer 2

Answer:

2:1

Explanation:

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