Physics, asked by tatipandurangrao, 4 months ago

Two like charges of magnitude 10-9 coulomb each are seperated by a distance of 2m in free space If the distance between the charges is increased to 4m then the ratio of electric potential energy is​

Answers

Answered by st4274387
2

Explanation:

Both charges have same charge of equal magnitude so, let q1 = q2 = q, d = 2m and d' = 4m. This is our required ratio.

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