Two like charges ratio 1:4 are 30cm apart the resultant field strength vanish at distance from smaller charge
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Answered by
0
Answer:
Let at a distance x from the smaller charge, E be zero.
E due to Q = E due to 4Q
⇒
x
2
kQ
=
(30−x)
2
k4Q
⇒
x
1
=
30−x
2
⇒30−x=2x
⇒30=3x
⇒x=10 cm.
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