Physics, asked by neena3073, 4 months ago

Two like charges when placed in a medium of dielectric constant of 2.5 at a distance of 10cm repel each other with a force of 1N . What will be the force of attraction when placed in 5cm apart in air

Answers

Answered by priyadatha
2

Answer:

10N

Explanation:

when placed in dielectric F'=F/K

where F is force in air

since F=kq²/r² F is inversely proportional to square of distance too

F=F'*K*(r'/r)²

=1*2.5*2²

=10N

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