Two like charges when placed in a medium of dielectric constant of 2.5 at a distance of 10cm repel each other with a force of 1N . What will be the force of attraction when placed in 5cm apart in air
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Answer:
10N
Explanation:
when placed in dielectric F'=F/K
where F is force in air
since F=kq²/r² F is inversely proportional to square of distance too
F=F'*K*(r'/r)²
=1*2.5*2²
=10N
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