two like parallel forces 20N and 30N act at the ends A and B of a rod 1.5 m long.The resultant of the forces will act at the point ?
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Lets assume the point at which resultant of the forces will act, is 'x' m from the point A.
Thus the point is (1.5 - x) m far from the point B.
Thus, using the formula Torque = Distance x Force acting
20x = 30(1.5 - x)
or, 2x = 4.5 - 3x
or, 5x = 4.5
or, x = 0.9
Thus the resultant point will be 0.9 m far from point A.
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