Two like parallel forces of 50N and 200N are 1m apart. Find resultant
A) R=50N
B) R=200N
C) R=250N
D) R=150N
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Answer: (c) 250 N
Explanation:
We know like forces adds up.
The resultant force is R = 50 + 200 = 250 N.
Position of the resultant force:
To find the position (x) of the force we use the analog of the formula to find the centre of mass.
In this case the forces take place of the masses. So take the sum of the product of each force with its position (with respect to some origin) and that equals the product of resultant force with its position x.
Taking the 50N as origin, we have,
50 (0) + 200 (1) = 250 (x)
or, x = 200/ 250 m = 4/5 m = 0.8 m .
So the resultant force has magnitude 250 N and acts at a distance of 0.8 m from the 50 N force.
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