Question

two like point charge separated by a certain distance exert a force of 0.04 N on each other when the distance of separation between them is halved the force exerted by each on the other will be

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Answer 1

Explanation:

The equation for force is

F1 = k×q1×q2/d²

Let F1 be the force for distance d,

Now if d is halved,the equation will be,

F1 = k×q1×q2/(d/2)²

F1 = 4×k×q1×q2/d²

Which is, F = 4F1

Where F is the force when distance is halved.

F = 4F = 4×0.04 = 0.16 N.

Answer 2

From the given question the correct answer is:

two like point charge separated by a certain distance exert a force of 0.04 N on each other when the distance of separation between them is halved the force exerted by each on the other will be  0.16N

The equation for force is

F1 = k×q1×q2/d²

Let F1 be the force for distance d,  

Now if d is halved,the equation will be,  

F1 = k×q1×q2/(d/2)²  

F1 = 4×k×q1×q2/d²  

Which is, F = 4F1

Where F is the force when distance is halved.

F = 4F = 4×0.04 = 0.16N