Question

two line cut the axis of X at a distance of 4 and -4 and the axis of y a distance 2 and 6 respectively find the coordinates of their point of intersection​

Answer 1

Answer:

( 1 , 1.5  )

Step-by-step explanation:

x/4 + y/2 = 1

x/-4 + y/6 = 1

4y/6 = 1 , y = 3/2 ,  x = 1

p = ( 1 , 1.5  )

Answer 2

Answer:

(-2,3)

Step-by-step explanation:

The first straight line has X-axis intercept 4 and Y-axis intercept 2.

So, the straight line has equation x/4+y/2 =1 ......... (1)

{Intercept form of straight line}

Again the second straight line has X-axis intercept -4 and Y-axis intercept 6.

So, the straight line has equation x/-4+y/6 =1 ......... (2)

Now, adding equations (1) and (2), we get,

y/2+y/6 =2

⇒4y/6 =2

⇒ y=3.

Now, from equation (1), we get, x/4= 1-(3/2)=-1/2

⇒ x= -2.

Hence, the point of intersection of (1) and (2) will have coordinates (-2,3). (Answer)