two line segment ab and CD are intersected at point O such that AOC is equals to 90 degree and OA equals to OB to prove that ca = cb
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In triangles OAC and OBC,
Side OC is common,
Side OA = side OB.
∠AOC = 90° = ∠COB (by geometry)
Therefore, the triangles are congruent, by SAS.
Therefore, CA = CB.
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